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Modificato da Sapid:
2/7/2013 8:36:26 PM
5
Math help!
EDIT: Solved! Thanks for the help.
I've been at this forever, so I finally gave up and I'm going to try here....
J+2T=9
J+4L=9
.5J+3T+2L=15
I need to find one J, one T, and one L. I've only been taught elimination and substitution (and graphing) so our teacher gave us this problem to try out. Problem is its a lot more difficult then the ones we go over in class.
I know the answers are (from asking a fellow classmate)
t=3.5
j=2
L=1.75
But I have no idea HOW to get those answer, and I need to show my work! Does anyone know how you would use elimination and substitution (and graphing) to get the answer??
TL;DR
J+2T=9
J+4L=9
.5J+3T+2L=15
Using elimination/substitution/graphing how would I get the answer?
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Thank you everyone. I understand it now, don't know what threw me off. Again, thanks for the help, I got it now!
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Modificato da Mitochondrion: 2/7/2013 8:33:25 PMUse a graphical calculator I used the function "simultaneous equations", then I used "3 unknowns", then I assigned first unknown as J, second as 3, 3rd as 2L and constant as 15 Plug in the values for the three constants and you use the numbers in front of the variables. If the variable doesn't have a number in it, put the number of the unknown variable as "1". If it doesn't feature in one of the equations, put "0". I got "x=2" y=3.5 z=1.75 Plug in the letters for x is J y is T and z is L and hey presto you got your variables.
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First reorganize the top and middle equations to T=(9-J)/2 and L=(9-J)/4 respectively. Then substitute your T an L variables with your new reorganized equations (that are now in terms of J) into the last equation. Solve this new equation to find your J value. Finally, place your J value into the top two equations and solve for your T & L values. You can also use Gaussian Elimination with the matrix: 1 2 0 9 1 0 4 9 .5 3 2 15 Good luck.
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.5J+3T+2L=15 -1.5(J+2T=9) [u]-0.5(J+4L=9)[/u] -1.5J=-3 J=2 Then just plug J into the other two equations to get the values for T and L.
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Modificato da Hylebos: 2/7/2013 8:21:05 PMOn second though, why the hell am I solving for things in terms of T when we have everything in terms of J? Solve T in terms of J, then solve L in terms of J, then substitute into the 3rd eqution to get J by itself and solve for J, then plug it back into the others.
