I think it is 2 because the orbital notation ends with 4s(2) but I have been looking for confirmation on the internet and I am getting different answers. Some sites say that the d orbital must be accounted for, too--so the 3d(7) plus the 4s(2) would equal 9 valence electrons. I am unsure, could I get some clarification, please?
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The valence electrons are the 4s2 and 3d7 electrons. Those are the outer most in the electron cloud.