{{
`${userDetail.user.displayName}${userDetail.user.cachedBungieGlobalDisplayNameCode ? `#${standardizeBungieGlobalCode(userDetail.user.cachedBungieGlobalDisplayNameCode)}` : ""}`}}
{{getUserClans()}}
Edited by Neno is drunk:
9/10/2015 11:36:23 PM
1
Wow, what a pain in the ass. Try plugging the answer into the x of this function
((sqrt ((((((3x)+((3/4)(3x))/7)-(((3x)+((3/4)(3x)+((3/4))(3x))/7)(1/3)(((3x+((3/4)(3x))/7)-(((3x)+((3/4)(3x))/7)(1/3)))-52)+8)÷10=2
I would have done the algebra part and plugging it in part, but I can't be assed to write everything down for 10 min. Besides, finding the function seems like the most important part anyway.
[spoiler]It should be right but idk. There's a chance I might have missed a parenthesis somewhere.[/spoiler]
English
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Edited by DarkSpyda04: 9/11/2015 7:26:38 PMThe way you wrote it makes it seem even more complicated. Try... (3x + (3/4 * 3x))/7 = x1 ((x1 - (1/3 * x1))^2) - 52 = x2 ((√x2) + 8)/10 = 2 ([b]3*28[/b] + (3/4 * [b]3*28[/b]))/7 = x1 ((x1 - (1/3 * x1))^2) - 52 = x2 ((√x2) + 8)/10 = 2 ([b]84[/b] + (3/4 * [b]84[/b]))/7 = x1 ((x1 - (1/3 * x1))^2) - 52 = x2 ((√x2) + 8)/10 = 2 ([b]84 + 63[/b])/7 = x1 ((x1 - (1/3 * x1))^2) - 52 = x2 ((√x2) + 8)/10 = 2 [b]147/7[/b] = x1 ((x1 - (1/3 * x1))^2) - 52 = x2 ((√x2) + 8)/10 = 2 [b]x1 = 21[/b] (([b]21[/b] - (1/3 * [b]21[/b]))^2) - 52 = x2 ((√x2) + 8)/10 = 2 ((21 - ([b]1/3 * 21[/b]))^2) - 52 = x2 ((√x2) + 8)/10 = 2 (([b]21 - 7[/b])^2) - 52 = x2 ((√x2) + 8)/10 = 2 ([b]14^2[/b]) - 52 = x2 ((√x2) + 8)/10 = 2 [b]196 - 52[/b] = x2 ((√x2) + 8)/10 = 2 [b]x2 = 144[/b] ((√[b]144)[/b] + 8)/10 = 2 ([b]12 + 8[/b])/10 = 2 [b]20/10[/b] = 2 2 = 2
