[b]Regarding #2, that is not how probability works[/b].
[b]Your probability of receiving a gjallarhorn after 4 engram decodes with a 1/4 (25%) drop rate is a 68.38% chance. [/b] I will now explain why.
A common misconception is that you are guaranteed that item when you decode an engram x number of times, where 1/X is the drop rate. (In your scenario, 1/4 ~ 25%)
Your mathematical probability actually never changes, you are never guaranteed anything.
The probability that your engram will drop the item at least once in x decodes is 1 minus the probability that it will not drop that item in x decodes, or
1 - (1 - y)^x
where x= number of decodes, and y= drop rate.
Thus, in your gjallarhorn example of a 25% (1/4) drop rate on engrams, the actual probability of receiving a gjallarhorn after 4 engram decodes is represented by this equation:
1 - (1 - (1/4))^4
1 - (3/4)^4
And your actual probability of receiving a gjallarhorn after 4 engram decodes is
[b]68.38% chance.[/b]
[i](Similarly you can solve how many attempts would be necessary to earn a 90% favor with the equation 1 - (1-y)^x > .9)[/i]
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Yay nerds!!!
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oh what fun!
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You're not wrong. But the expected number of trials--the average of the distribution--is still 4.
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I take it you have some experience in statistics, same here. Thanks for the feedback, but due to the phrasing of the question and saying "on average" and "expected", we can use the formula 1/p where p is the probability of success. This doesn't guarantee it, and I have to remove the guarantee part of it, but in theory we expect 4 trials before a Ghorn is achieved.