Calculus tutor here.
The standard form of a natural log derivative is ln(x) -> 1/x. In this case, we have ln(T-8), so we'll need to use the chain rule. Our outer function is ln(inner), our inner function is T-8, the derivative of the outer function is 1/(inner), the derivative of the inner function is just 1, so putting it all together we end up with 1/(T-8).
English
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Oh I see, we count T-8 as x. Okay, I think I understand it now.
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Sort of. Just remember that if it were something like ln(T^2 - 5), the derivative of the inside function would be 2T, so the resulting derivative would be 2T/(T^2 - 5).
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Got it.