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originally posted in: Algebra help
3/11/2013 3:06:04 AM
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I understand how to do the problem, but I am too lazy to actually do it. Honestly I don't see why you can't do it OP?
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  • Well at first thought it's the ''exactly divisible'' that boggles my mind, if when divisible by (2x-1) it gave a remainder then yeah I would be able to do it, but I just can't seem to think straight at this one particular question, sorry.

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