Just try to solve it... just try...
[spoiler]For all those that said "no solution" or "false" congratulations you win!!![/spoiler]
[spoiler]And for people like LIGHTZEAL... IT ISN'T SOLVABLE...
Apparently there is a way to
solve it... [/spoiler]
English
#Offtopic
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Edited by Tamedfrog: 10/4/2014 2:09:19 AMPlauses
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Edited by Vicex: 10/1/2014 5:55:29 PMA = Infinity Only Buzz lightyear can go beyond infinity.
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For the last time let me try and explain to you non-believers. Replace A with the square root of .25. So now you have square root of .25 + 1 = square root of .25. Now square root of .25 can either become .5 or -.5. Because -.5*-.5=.25 And .5*.5=.25 So we get -.5+1=.5 [spoiler]easy, trust me I'm an engineer[/spoiler]
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Vicex said infinity=A. Wouldn't that work?
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whats with all the math threads?
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Such bad math in this thread. Please kiddos, stay in school. There is no solution such that A+1 = A. If you have any background in mathematical proof, this should be pretty self-evident. I guess if you limited yourself to a system where everything was mod 1 it could work, but that isn't what was said (and would be pure nonsense anyway).
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E=MC vagina
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Edited by LegendOfWinter: 10/2/2014 3:26:21 PMThe solution!
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Edited by Zeal: 10/2/2014 9:53:34 PMWait I got this. A^2 + 2A +1 = A^2 2A=-1 A=-.5 [spoiler]thjs is only the beginning to the working out read my other post[/spoiler]
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Just the equation to gradual growth, not solvable but not without a solution.
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t(n+1)=(t(n)*4)+3 Explain to me how THIS equation works.
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Edited by Shortbusregular: 10/2/2014 2:08:37 PMReason why it's no solution: A-1=A -A. -A -1=0 -1 does NOT equal 0
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Tried googling this to see if I was right. Can't find. I will call this equation the zeal theorem.
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What's with all this... Math... *shudders*
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I am still right right[spoiler]if you say yes you get cake and ice cream[/spoiler]
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I'm sorry I didn't realize we were going back to 5th grade math
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No where in all of math could there be a solution. Even with infinity and imaginary numbers it would be impossible.
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No solution or false.
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Edited by Jotaro Kujo PhD: 10/2/2014 12:51:56 AM50/50 It's either solvable or it isn't [spoiler]( ͡° ͜ʖ ͡°)[/spoiler]
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it's true if A is a constant of integration
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Edited by Mechetti: 10/2/2014 12:01:41 AM_ _ A=-.1
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100th post!!!!!! Give me teh lobe
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Another variable will have to be used on the right sign of the equation. A+1 cannot equal A. Because it will be A+1. Now if A+1 equals B. We can solve it.
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You forgot to make one of the "A's" lowercase.
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That's a mathematically false statement. A+1 can't be equal to A because it is 1 friggin more than A!