{{
`${userDetail.user.displayName}${userDetail.user.cachedBungieGlobalDisplayNameCode ? `#${standardizeBungieGlobalCode(userDetail.user.cachedBungieGlobalDisplayNameCode)}` : ""}`}}
{{getUserClans()}}
11/16/2012 7:02:47 AM
6
any math wizards online?
In Angry Birds, your bird launching catapult is at the top of a tower 10m high. You launch your bird with a velocity of 10m/s at an angle of 30o. How far from the base of your tower will the bird land? Assume acceleration due to gravity is -9.81m/s2. Assume no friction
Help me please
-
Vx = 10cos(30) You need to find t, the time it takes to hit the ground. You do this by finding Vy (10sin(30)), and using a = -9.81, and an additional height of 10m, solve for t. Using x = .5a(t^2) + v_0(t) + x_0 x_vertical = .5(-9.81)(t^2) + (10sin(30))t + 10 = 0 x_horizontal = .5(0)(t^2) + (10cos(30))t + 0 Do you understand why acceleration for the horizontal distance is zero? [Edited on 11.15.2012 11:38 PM PST]
