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Edited by Satan:
12/5/2014 3:23:48 AM
15
Need math help
"The cost of an SAT prep class for q students is 700-10q per student. If the SAT prep company wants to maximize it's profit, how many students must sign up and what price will each student pay?"
I don't just want the answer, I need to know how to do the problem.
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Edited by H2O: 12/5/2014 1:06:07 PM700 - 10q is your function. Use first and second derivatives to do an optimization. I can do the math later to see if there's something missing. I need practice for my final anyway Edit: As far as missing information goes, I don't immediately see a constraint equation, but I could very easily be overlooking something.
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Sir is the question right??
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(0) +(3) + (0) = ( ͡° ͜ʖ ͡°)
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Pretty sure there is some missing information for the answers you are looking for. Either that, or the questions you are asking are incorrect.
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2 RepliesIs this supposed to be an optimization problem where you need to use first and second derivatives? What math class?
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3 RepliesThis is similar to revenue questions. The your basic formula is (# of students)( price )= cost. Now, I'm not sure if I'm doing this part right, but you should get something like this: (700+q)x(700-10q), where q is your number of students. Foil that out, and then either punch it into a graphing calculator and find the vertex or change the equation to vertex form and do the same. That will show you the number of Students that must attend and the price per ticket. Hope I'm doing that right lol.
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All you need to know is the number of the beast.
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3 RepliesWhat's sat
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2 RepliesI don't understand 700-10p.
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4 Replies[quote]10p[/quote] Is this some sort of currency? I can help, I just don't what the p means.
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Here's what you do: First split up the 700 into smaller digits that are easier to understand. Such as 7*10*10, or (3+4)*(5*2)*(5*2) = (3+2+2)*(5*2)*(5*(1+1)) Now that we know that 700 is equal to this we replace it in the equation: (3+2+2)*(5*2)*(5*(1+1)) - 10p Next we work with the 10. 10 = 5*2 or (5*(1+1)) which as you can see we have in the first part. So now: (3+2+2)*(5*2)*(5*(1+1)) - (5*(1+1))p = (5*(1+1))((3+2+2)*(5*2)) - p) And with a simple use if vertex form, quadratic equations and some triple integration you get the answer as (7*((1+1)*(1+1+1)))
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1 ReplyQ is the amount of students.
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Blaming common core
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